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1 Rs 675
amount to Rs
837 in four
years at simple
interest . If the interest
rate is decreased by 2
% then amount
will be
A 729 b 753
c 763 d
783
S I for four
years 837-675= 162
Actual interest rate is
6 % if
2 % is
decreased ie 4
%
Then amount
is 783/-
Answer d
783
|
2 What least
number which must
be added to
1056 so that the
sum is completely divisible
by 23?
A 3 b 18
c 2 d 21
23) 1056 (45
92
---
136
115
---
21
---
Required number = (23 - 21)
= 2.
Answer c
2
|
3 In a
school with 600 students ,
the average age
of the boys
is 12 years
and that of
girls is 11 years
. if the
average age of the
school is 11 years and
9 months then
the number of
girls in the
school is
A 450 b 250 c 150 d
350
Let the number of
Girls be X
Then number of
boys = (600-x)
(11 4/3 * 600 )= 11 x 12 (600-x)
X=7200-7050 =150
Answer c
150
|
4 Ram bought
a cycle and
sold it for
Rs 4550 which is
30 % more than
this original price
. What is
the original price of
the cycle
A 3500/- b
3800/- c 3600/= d 3400/-
Let cost price (C.P.) = 100.
Profit = 30 %. Selling price (S.P.) = (100 + 30) = 130. If selling price (S.P.) is 130, then cost price (C.P.) is 100. If selling price (S.P.) is 1, then cost price (C.P.) is $ (100/130). If selling price (S.P.) is 4550, then cost price (C.P.) is (100 /130 × 4550) = 3500 Answer A 3500/- |
5 Rahim sales
a cow at a
loss of 15 %
. if he has
sold it for Rs 150 more
than he would
have made a
profit of 10 % .
Cost price of
the cow was
A 660 b
600 c 575
d None of these
Let cost price be P Sold price =85 % of P 85/100*P+150=110/100*P 25/100*P =150 25P=15000 P=15000/25= 600
Anser 600
|
6 There are
some parrots and some tigers
in a forest
. if the
total number of
animal heads in
the forest are
858 and total
number of animal
legs are 1746 .
What is the
number of parrots
in the forest
A 843 b
847 c 800
d None of these
Let the no
of parrots is
assumed as X
Total number of
animals = 858
Total tigers = 858-x
Total legs =
2x=4(858-x)=1746
=2x+3432-4x=1746
2x=3432-1746=1686
X=1686/2=843
Answer a
843
|
7 LCM of 36 , 45,52, 108 and 236 is
a
A 414180 b 480414
c 441180 d
none of these
36 = 2*2*3*3*
45 = 3*3*5 52 = 2*2*13 108 = 2*2*3*3*3* 236 = 2*2*59 Therefore, L.C.M of 36, 45, 52, 108, 236 = 2*2*3*3*3*5*13*59 = 414180
Answer a 414180
|
8 Salaries of Akash , Babloo and
chintu are in
the ratio of
2:3:5 . If
their salaries were
increased by 15 %
, 10 % and
20 % respectively
What will be the
new ratio of their
salaries
A 3:3:10 B 23:33:60
C 20:22:40 D
None of these
Let Akash =
2 Babloo = 3
and Chintu =
5
Then 100/115=2 =
23/10
100/110=3 = 33/10
120/100=5= 6
Then new ratio
is 23/10 :33/10: 6 =
23:33:60
Answer b
23:33:60
|
9 A man earns Rs
20 on the first
day and spends
Rs 15 on
the next day
. He again
earns rs 20
on the third
day and spends
rs 15 on
the fourth day
. if he
continues to save
like how soon
will have Rs
60 in hand
A on 30
the day b
On 40th Day c
On 27th Day D
On 17th day
Explanation: Money earned in 2 days = Rs.(20 - 15)
= Rs. 15. Money earned in 16 days = Rs.(5/2 x 16) ‹=›Rs. 40. On 17th day, money in hand = Rs.(40 + 20 ) = Rs. 60.
Answer d
17th Day
|
10 Ajay can do
a piece of
work in 25
days and Sanjay
can finish it
in 20 days
. They work together for
5 days and
Ajay goes away
. In how many
days will Sanjay
finish the remaining
work
A 11 days
b 12 days c 14 days
d None of these
1 days work of Ajay =1/25 Sanjay = 1/20 So (Ajay+Sanjay)= 1/25+1/20=9/100 5 days work of Ajaya and Sajay=45/100 Remaining work = 1-45/100=55/100 Sajay can do 55/100 work in 55/100/1/20 = 11 Days
Answer a 11 Days
|
11 The decimal representation of a
rational number is
A Always terminating
b Either terminating
or repeating c Either
terminating or non
repeating
Answer b
|
12 A hemispherical bowl
of internal radius
9 cm contains
a liquid , The
liquid is to be
filled into cylindrical
shaped small bottles
of diameter 3
cm and height
4 cm .
How many bottles
will be needed
to empty the
bowl
A 45 b 54
c 35
d 48
Radius of hemisphere= 9 cm
volume of hemisphere= 2/3 π r3
= 2/3 x9x9x9 π
= 486 π
radius of cylindrical shaped bottles= 3/2 cm
height= 4 cm
volume of bottles= π r2h
= 3/2x 3/2 x 4 π
=9 π
now,
Reaquired no. of bottles= volume of hemisphere/ volume of bottles
. =486 π/9π
. =54
Hence, no. of bottles required to empty the bowl = 54
Answer b
54
|
13 If the
numerator of a
fraction is increased
by 200 % and
the denominator is
increased by 300 %
the resultant fraction
is 6/11 . What
was the original fraction .
A 5/11 b
7/11 . c 8/13
d 8/11
If numerator increase
200 % then Numerator will be x+2x =3x
and denominator increased by 300% means denominator will be y = 3y =4y new fraction will be 3x/4y =6/66 (g
3x/4y = 6/11
dividing numerator by 3 and denominator by 4 both side we will get x/y =6/3/11/4 x/y=6x4/11x3 x/y =24/33 x/y =8/11 Answer d 8/11 |
14 If the
ratio of areas of
two squares is
9:1 the ratio
of perimeter is
A 3:1 b
1:2 c 3:2
d None of
these
|
15 40 Laourers can
handle a task
of debri clearance
in 7 days
. if 5
% of the
labourers leave after
2 days .
What is the
total number of days
the task will
take
A 5 5/19 b 5 ½
c 5 7/8
d 5 8/19
|
16 If eggs are
bought at 10
for Rs 8
and sold at 4 for
Rs 5 the
business result in
A 50 %
loss b 56 1/3
% gain c
51 % gain
d 56 ¼
% gain
Answer 56 ¼ % gain
|
17 A fruit
seller buys lemons
at 2 for
a rupees. His
gain percent is
A 10 %
b 15 % c 20
% d 25 %
Answer 20 %
|
18 A car is
moving with a speed
of 36 km/h .
How much time
in seconds it
will take to
cross a 500 m
long bridge .
A 40 b
45 c 50 d 55
Speed 36 KM/H = 36*5/18 M/S =10 M/S So time taken to cross 500m bridge = 500/10 = 50 Second Answer 50 |
19 Two cars
start from the
same point at
8 am . In the
same direction .
The speed of the first car
is 60 km/h
and the speed
of second car
is 55 km/h
. The distance
between them at
2 p. m on
the same day
is
A 20 km
b 25 km c 28
km d 30 km
Time duration 14-8 = 6 Hrs 2 PM ( 14 hrs)
distance by first car 6*60 360 KM Distance by IInd car = 6*55 =330 KM So distance between two car 30 KM Answer 30 KM |
20 The distance
between two cities A
and B is
520 km . One
car starts from
city A towards
city B with
the speed of
60 km/h. At
the same time
another car starts
from city B
towards city A
with a speed
of 70 km/h .
After how many
hours they will
cross each other
A 3 hours b
4 Hours d 5
hours d 6
hours
Let distance travelled by A= X Distance travelled by B= (520-X) X/60=520-x/70 70X=(520-X)60 70X=520*60-60X 130X=520*60 X=240 ie Time =240/60= 4 Hrs Answer 4 Hrs |
21 A
car towards 50 km
in first hour
, 60 Km
in second hour
and 43 km
in third hour .
The average speed
of the car
is
A 43 KM/h
b 50 KM/h
c 51 KM/h
55 KM/h
153/3 Answer 51 KM/h |
22 A car
travels a distance
of 150 km in 3 hours and
next 242 km
in 4 hours .
The average speed of
car for complete
journey
A 50 km/h b
55.25 km/h c 56 km/h
d 58 km/h
Answer 56 KM/ h |
23 If
the diagonals of a
rhombus are of
measure 12 cm
and 16 cm .
then this measure
of its side
is
A 10 cm b 20 cm
c 15 cm d 96
cm
12/2 cm = 6 cm and 16/2 cm = 8 cm long.
Answer a 10
cm
|
24 A watch
was sold at
a profit of
15 % . If
its cost had
been 5 % less and
it had been
sold for Rs
21 less , then
the profit would
have been 10
% . Find the
cost price of
the watch
A 200 b 400 c
190 d None
of these
Answer 200 |
25 60 % of
the students in
a school are boys
. if the
number of girls
in the school is
300. Then the
number of boys
is
A 500 b
300 c 450 d 750
If 60% are boys, then 40% must make up the girls.
Let x = total number of students
then .40x = 300 x = 300/.40= 7.5*100=750
750-300=450
Total no of
boys 450
Answer c
450
|
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Monday, 16 September 2013
Solved questions - LGO Exam held on dated 15.09.2013
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THANK U VERY MUCH GREAT JOB.....
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